47g^2+2g=0

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Solution for 47g^2+2g=0 equation: 



47g^2+2g=0

a = 47; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·47·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*47}=\frac{-4}{94}
=-2/47
$


$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*47}=\frac{0}{94}
=0
$

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